A father is 4 times as old as his son and the son is 36 years younger than the father
Find their ages.
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A father is 4 times as old as his son and the son is 36 years younger than the father
Find their ages.
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Answer:
Step-by-step explanation: Hii friend,
Let the age of father and son be X and Y year's.
According to question,
X = 4Y.....(1)
Again,
Y = X-36.....(2)
Putting the value of X in equation (2)
Y = X-36
Y = 4Y -36
4Y-Y = 36
3Y = 36
Y = 36/3
Y = 12
Age of son = Y = 12 years.
And,
Age of father = 4Y = 4 × 12 = 48 years.
Hence,
Age of father and son is 48 and 12 years.
HOPE IT WILL HELP YOU...... :-)