if a-3=10/a, find the value of a
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Step-by-step explanation:
(a-3)a=10
[tex]a^{2}[/tex]-3a=10
[tex]a^{2}[/tex]-3a-10=0
this is a quadratic equation
so......by mid term splitting
[tex]a^{2}[/tex]-5a+2a-10=0
a(a-5)+2(a-5)=0
(a+2)(a-5)=0
so a can be -2 or 5
ghope you understood the question mark brainliest plzzzzz
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