a force of 5n acting on a body at an angle of 30degree with the horizontal displaces through a distance of 6m calculate the work done
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a force of 5n acting on a body at an angle of 30degree with the horizontal displaces through a distance of 6m calculate the work done
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Verified answer
Given:-
→ Force = 5N
→ Angle of displacement = 30°
→ Displacement = 6m
To find:-
→ Work done
Solution:-
We know that:-
W = F × s × cosθ
Where:-
• W is work done.
• F is magnitude of force.
• s is displacement of the body.
→ Value of cosθ at 30° = √3/2
=> W = 5 × 6 × cos 30°
=> W = 30 × √3/2
=> W = 15√3 J
Thus, work done is 15√3 J .
Some Extra Information:-
• Work done by a force on a body is the product of force and displacement of a body.
i.e. W = F × s
• Work is a scalar quantity which means it
has no sense of direction.
• The S.I. unit of work is Joule. The C.G.S
unit of work is erg.