A freely falling body covers 44.1m in the last second of its journey. Find the total distance travelled by the body.
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A freely falling body covers 44.1m in the last second of its journey. Find the total distance travelled by the body.
Please answer this fast..it's urgent..please
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Explanation:
d=ut + 1/2 at^2
Now at t = t-1
d'=u(t-1)+1/2a(t-1)^2
Here u =0 and a = g= 10 m/s^2(approx)
d=5t^2
d'=5(t-1)^2
d-d'=44.1 m = 5[2t-1]
8.82 = 2t-1
4.96 = t (Approx 5 sec)
Now,
d= 5*(5)^2
d= 125 m.
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P.S:
If more accurate answer is required then take g=9.81 m/s^2.