A fruitseller buys some orange at the rate of 4 for a rupee and an equal number at 5 for a rupee.
He sells the whole lot at 9 for two rupees. Find his gain or loss per cent.
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A fruitseller buys some orange at the rate of 4 for a rupee and an equal number at 5 for a rupee.
He sells the whole lot at 9 for two rupees. Find his gain or loss per cent.
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C.P. of 1 orange of 1 st kind =Rs
4
3
=Rs0.75
And C.P. of 1 orange of 2 nd kind =Rs
5
3
=Rs0.60
On, mixing C.P. of 2 oranges =0.75+Rs 0.60=Rs 1.35
And S.P. of 2 oranges =Rs 2×0.9=Rs 1.80
Now, Since S.P.>C.P. there is a gain
So, Profit % =
C.P.
S.P−C.P.
×100=
1.35
1.80−1.35
×100=
135
45
×100=3331 %
Answered By=shreyash. ....
Answer:
Let the fruit seller buys x number of oranges each time
A fruit seller buys some oranges at the rate of 4 for Rs 10
Each orange cost = ₹10/4 = ₹2.50
x number of oranges cost = ₹2 50 × x = ₹2 50x
and an equal number more at 5 for Rs 10.
Each orange cost = ₹10/5 = ₹2
Again x number of oranges cost = ₹2 × x = ₹2x
Total cost = ₹2.50x + ₹2x = ₹4.50x
Total oranges = x + x = 2x
Average cost of each orange = ₹4.50x/2x = ₹2.25
He sells the whole lot at 9 for Rs 20
Sale price of each orange = ₹20/9 = ₹2.22222
Cost price of each orange is more than its sale price therefore there is loss on the sale of oranges
Loss = cost price - sale price
Loss on each orange = ₹2.25 - ₹2.22222 = ₹0.02778
There is loss of ₹0.02778 on each orange thus on 100 oranges there is loss as below
Percentage loss = 0.02778 × 100
= 2.778% loss
Step-by-step explanation:
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