a glass cylinder with diameter 20cm has water to a height of 9 CM a metal cube of 8 cm at is immersed in it completely calculate the height of by which water will rise in the cylinder
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a glass cylinder with diameter 20cm has water to a height of 9 CM a metal cube of 8 cm at is immersed in it completely calculate the height of by which water will rise in the cylinder
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Total volume of cylinder (after cube was immersed) = Volume of water in cylinder + (Volume of water displaced or volume of cube)
= pi*r2h+a3
=22/7 *102*9+83
=(19800+3584)/7
=23384/7
Now, height of water h1 for this volume can be found by equating pi*r2h1 with this volume:
So, 22/7 *102*h1 = 23384/7
h = 23384/2200 = 10.63 cm
Rise in water level = h1 -h = 10.63-9 = 1.63cm
Answer:
H = 9 cm
diameter = 20 cm so,radius = 10 cm
side of the cube = 8 cm
Total volume of the cylinder
(after cube is immersed) = Volume of water in cylinder + Volume of water displaced or volume of the cube
= 22/7*10*10*9 + 8*8*8
= 19800/7 + 512
= 2828.57 + 512
= 3340.57 cu cm
Now, height of water, h1 can be found by equating πr²h1 with this volume.
So,
22/7*10*10*h1 = 3340.57
h1 = (3340.57 × 7)/2200
h1 = 23383.99/2200
Height = 10.63 cm
Rise in the water level in the cylinder
= h1 - h
= 10.63 - 9
= 1.63 cm