A glass stopper of 20 cm^3 volume and weight as 50 g-wt, as observed by using a spring balance, is taken and immersed completely in tap water. What will be the amount of up thrust and apparent weight of glass stopper?
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A glass stopper of 20 cm^3 volume and weight as 50 g-wt, as observed by using a spring balance, is taken and immersed completely in tap water. What will be the amount of up thrust and apparent weight of glass stopper?
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Upthrust force acting on body = Weight of water displaced by the body
As stopper volume = 20 cm^3 thus it can only displace 20 cm^3 of tap water
Also we know density of water = 1 g/cm^3
Therefore the weight of water displaced = 1×20 -20g
(Weight = Density × Volume )
Thus Upthrust = 20g or .2N (force = mass × gravitational acceleration)
NOTE: Here I taken gravitational acceleration = 1 O m/s^2
Now,weight of stopper will be reduced by the upthrust by 20g as it act against the body weight
Thus, Apparent Weight = 50 -20= 30g
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Explanation:
The three most common methods are basin irrigation, border irrigation and furrow irrigation. Water is typically introduced at the highest point or along the edge of a field, which allows covering the field by overland flow.