a healthy person eats the following diet -5 gram raw sugar, 4 gram albumin, 10 gram pure buffalo ghee adulterated with 2 gram vegetable ghee( hydrogenated vegetable oil) and 5 gram lignin. How many calories he is likely to get?
a healthy person eats the following diet -5 gram raw sugar, 4 gram albumin, 10 gram pure buffalo ghee adulterated with 2 gram vegetable ghee( hydrogenated vegetable oil) and 5 gram lignin. How many calories he is likely to get?
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
5×4.0= 20 kcal
4×4.0= 16 kcal
(10+2)=12×9.0= 108kcal
Ans. 144 Kcal
Answer:
144.8cal
Explanation:
The amount of calorie intake of the person depends on the calorific value of the food he is in taking.
The calorific value of a food is the calorie it gives per gram of its intake.
So according to this:
5g sugar (carbohydrate)
4g albumin (protein)
10 + 2g oil (fats)
Lignin is not digested in our body, so have no calorific value.
So, total calorie comes out as 144.8cal.