A his daugh Seven years ago, I was seven times as old as you were then
the years from me I shall be three times as old as you will be on the
resting present this situation algebraically and graphically
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A his daugh Seven years ago, I was seven times as old as you were then
the years from me I shall be three times as old as you will be on the
resting present this situation algebraically and graphically
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Answer:
Let the fathers age be x years and his son be y years.
Therefore, seven years ago, age of father = (x-7)
and age of son = (y - 7)
According to the given condition,
x-7 =7(y-7)
or x-7y = -42 ...(1)
After 3 years, fathers age = x+3 and
son's age = (y+3)
As per given condition,
x+3 = 3(y+3)
x-3y = 6 ...(2)
ON subtracting (2) from (1), we get
x - 7y - (x -3y) = -42 - 6
⇒ -4y = -48
⇒ y = 12
On putting value of y in (2), we get
x - 3(12) = 6
⇒ x = 6 + 36 = 42
Hence, present father's age = 42 years
and present son's age = 12 years
Step-by-step explanation:
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