a hollow spherical iron shell has an internal radius of 3 cm and external radius of 6cm. how much iron is there in there in the shell? with solution plz friends with whole solution plz
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a hollow spherical iron shell has an internal radius of 3 cm and external radius of 6cm. how much iron is there in there in the shell? with solution plz friends with whole solution plz
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Answer:
Internal radius = r = 3 cm
external radius = R = 6 cm
Volume of Iron = Volume of External Sphere Shell - Volume of Internal Sphere
[tex] = \frac{4}{3} \pi {R}^{3} - \frac{4}{3} \pi {r}^{3} \\ = \frac{4}{3} \pi( {R}^{3} - {r}^{3} ) \ \ \\ = \frac{4}{3} \times \frac{22}{7} ( {6}^{3} - {3}^{3} ) \\ = \frac{4}{3} \times \frac{22}{7} (216 - 27) \\ = \frac{4}{3} \times \frac{22}{7} \times 189 \\ = \frac{4 \times 22 \times 27}{3} \\ = 88 \times 9 \\ = 792 \: {cm}^{3} \\ [/tex]