A large water tank begins to leak at the rate of 25 litres per hour. The amount if water escaping is 25 litres more than the previous hour till the leak was undetected. When the leak was eventually discovered the rate of leakage was 900 litres per hour. For how long had the tank been leaking? What was the total amount of water lost between the beginning of the leakage and the time of discovery?
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Answer:
Step-by-step explanation:
Starting leakage 25 liter per hour then increases next hour 50 lit similarly .....
25 , 50 ,75 , .......900
a= 25
d= 25
tₙ=a +(n-1)d
900=25 (n-1)25
n=36
36 hrs tank had leakage
now Sn
Sn = n/2 [t₁+tₙ]
S₃₆= 36/2 [25+900]
S₃₆ = 18 × 925
S₃₆ = 16650 liter
Amount of water leakage 16650 liter .......
For a period of 36 hours the water tank leaked. The total amount of water lost between the beginning of the leakage and the time of discovery is 16650 liters.