A man make a short and a loud sound in front of a hill and the echo is heard after 3s. on moving closer to the hill by 165m the echo heard after 2s calculate the below of sound and the distance of the hill from the first position??????
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A man make a short and a loud sound in front of a hill and the echo is heard after 3s. on moving closer to the hill by 165m the echo heard after 2s calculate the below of sound and the distance of the hill from the first position??????
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Answer:
Explanation:
s = x
d = 165 m
t = 2 s /2 = 1 s ( divide the time by 2 - because it takes twice the amount of the actual
time of the sound waves to go and return.)
s = d / t
s = 165 / 1
s = 165 m/s ⇒ below speed of sound
s = 165 m/s
d = x
t = 3 s / 2 = 1.5 s
d = s * t
d = 165 * 1.5
d = 247.5 m ⇒ distance of hill from the first position