a man of mass m climbs up a hanging vertical rope for a distance d. work done, W, by friction force acting on his hands is
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a man of mass m climbs up a hanging vertical rope for a distance d. work done, W, by friction force acting on his hands is
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Answer:
man and the rope, the man will slide down the ground. It is the frictional force which take him in upward direction.
So,
F−mg=ma
F=mg+ma
F=m(g+a)↑
A man of mass m climbs up a hanging vertical rope for a distance d. Work done, W, by friction force acting on his hands is (md(g+a)).
[tex]F_{1} = mg[/tex]
[tex]F_{2} = f[/tex]
[tex]f - mg = ma[/tex]
[tex]f = mg + ma[/tex]
[tex]= m (g+a)[/tex]
[tex]W = f * d[/tex]
[tex]W = m(g+a) * d[/tex]
[tex]= md(g+a)[/tex]