A man starts his job with a certain monthly
salary and a fixed increment every year. If
his salary will be * 11,000 after 2 years and
14,000 after 4 years of his service, what
was his starting salary and what is the
annual increment?
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A man starts his job with a certain monthly
salary and a fixed increment every year. If
his salary will be * 11,000 after 2 years and
14,000 after 4 years of his service, what
was his starting salary and what is the
annual increment?
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Answer:
Let starting salary = x
Let starting salary = xIncrement every year = y
Let starting salary = xIncrement every year = yx +2y = 11,000 ....... eq(1)
Let starting salary = xIncrement every year = yx +2y = 11,000 ....... eq(1)x + 4y = 14,000 ......eq(2)
Let starting salary = xIncrement every year = yx +2y = 11,000 ....... eq(1)x + 4y = 14,000 ......eq(2)Substract eq(1) from eq(2)
Let starting salary = xIncrement every year = yx +2y = 11,000 ....... eq(1)x + 4y = 14,000 ......eq(2)Substract eq(1) from eq(2)2y = 3,000
Let starting salary = xIncrement every year = yx +2y = 11,000 ....... eq(1)x + 4y = 14,000 ......eq(2)Substract eq(1) from eq(2)2y = 3,000y = 1500
Let starting salary = xIncrement every year = yx +2y = 11,000 ....... eq(1)x + 4y = 14,000 ......eq(2)Substract eq(1) from eq(2)2y = 3,000y = 1500 Substitute y= 1500 in eq(1), we get x = 11,000 − 3,000
Let starting salary = xIncrement every year = yx +2y = 11,000 ....... eq(1)x + 4y = 14,000 ......eq(2)Substract eq(1) from eq(2)2y = 3,000y = 1500 Substitute y= 1500 in eq(1), we get x = 11,000 − 3,000x = 8,000
Let starting salary = xIncrement every year = yx +2y = 11,000 ....... eq(1)x + 4y = 14,000 ......eq(2)Substract eq(1) from eq(2)2y = 3,000y = 1500 Substitute y= 1500 in eq(1), we get x = 11,000 − 3,000x = 8,000starting salary = 8,000
Let starting salary = xIncrement every year = yx +2y = 11,000 ....... eq(1)x + 4y = 14,000 ......eq(2)Substract eq(1) from eq(2)2y = 3,000y = 1500 Substitute y= 1500 in eq(1), we get x = 11,000 − 3,000x = 8,000starting salary = 8,000 Increment = 1500
Answer:
Answer:
Step-by-step explanation:
Given,
A man starts his job with a certain monthly salary and a fixed increment every year.
Salary will be Rs. 11000 after 2 years and Rs. 14000 after 4 years of his service.
To Find,
Starting salary and Annual increment.
Solution,
Let starting salary of a man be Rs. x
And the fixed annual increment be Rs. y.
Now, According to the question,
⇒ x + 2y = 11000 _(i)
⇒ x + 4y = 14000 _(ii)
Now, On subtracting (i) from (ii), we get
⇒ 2y = 3000
⇒ y = 3000/2
⇒ y = 1500
Hence, the fixed annual increment of a man is Rs. 1500.
Now, On substituting y's value in eq (i), we get
⇒ x + 2y = 11000
⇒ x + 2 × 1500 = 11000
⇒ x + 3000 = 11000
⇒ x = 11000 - 3000
⇒ x = 8000
Hence, the starting salary of a man is Rs. 8000.