a man's present age is 8 times more than his son after 10 years he will be twice the age of his son how old is son at present
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a man's present age is 8 times more than his son after 10 years he will be twice the age of his son how old is son at present
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Answer:
Present age of son 1 year 2 months.
Step-by-step explanation:
Given :-
A man's present age is 8 times more than his son.
After 10 years, he will be twice the age of his son.
To find :-
Present age of son.
Solution :-
Consider,
The present age of son = x years
★ A man's present age is 8 times more than his son.
Then,
The present age of the man = 8x years
After 10 years,
Son's age = (x+10) years
Man's age = (8x+10) years
★After 10 years, he will be twice the age of his son.
According to the question,
8x+10 = 2(x+10)
→ 8x + 10 = 2x + 20
→ 8x-2x = 20-10
→ 6x = 10
→ x = 5/3
→ x = 1 year 2 months
★The Present age of son = 1 year 2 months.
★ Present age of man = 8 × 5/3 = 40/3 = 13 years 1 month.
Given :
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Find :
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Concept :
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Calculations :
→ 8x + 10 = 2(x + 10)
→ 8x + 10 = 2x + 20
→ 8x - 2x = 20 - 10
→ 6x = 10
→ x = 10/6
→ x = 5/3
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Finding their present ages :
→ Present age of Son = 1 year 2 months
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→ Present age of Man = 8 × 5/3
→ Present age of Man = 40/3
→ Present age of man = 13 years 1 month