A metal cube of edge 12cm is melted and formed into three smaller cubes. if the edges of the two smaller cubes are 6cm and 8cm , find the edge of the third smaller cube?
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A metal cube of edge 12cm is melted and formed into three smaller cubes. if the edges of the two smaller cubes are 6cm and 8cm , find the edge of the third smaller cube?
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Answer:
Edge of a bigger cube (R)= 12 m
Edge of a first smaller cube(r²)= 8 m
Edge of a second smaller cube(r2)= 6m
Volume of a cube = side³
Volume of a bigger cube(V) = (sides)³
= (12)³= 1728m³
It is melted into three other cubes ,so the volume of the smaller cubes remains same as the volume of bigger cube .
volume of the first smaller cubes(V1)= (8)³=512m³
volume of second smaller cube(V2) = 6³ = 216m³
Total volume(V) = volume of first smaller cube(V1) + volume of second smaller cube(V2)+ + volume of third smaller cube(V3)
V= V1+V2+V3
1728 = 512 +216+V3
1728 = 728+V3
1728 - 728 = V3
1000 = V3
volume of third cube = 1000 m³
Edge³= 1000
Edge = ³√1000
Edge =³√10×10×10
Edge= 10 m
Hence, the edge of the third cube is = 10m
Step-by-step explanation:
Answer:
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