A metal cube of side 5 cm at 28 degree Celsius on heating 2578 Celsius increases by 0.15 CM .Calculate the coefficient of linear expansion ,superficial expansion and cubical expansion
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A metal cube of side 5 cm at 28 degree Celsius on heating 2578 Celsius increases by 0.15 CM .Calculate the coefficient of linear expansion ,superficial expansion and cubical expansion
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Answer:
The coefficient of linear expansion (α) can be calculated using the formula:
\[ \alpha = \frac{\text{Change in length}}{\text{Original length} \times \text{Change in temperature}} \]
In this case, the change in length (\( \Delta L \)) is 0.15 cm, the original length (\( L \)) is 5 cm, and the change in temperature (\( \Delta T \)) is the final temperature (2578 °C) minus the initial temperature (28 °C).
\[ \alpha = \frac{0.15 \, \text{cm}}{5 \, \text{cm} \times (2578 \, \text{°C} - 28 \, \text{°C})} \]
Calculate this to find the coefficient of linear expansion.
The coefficient of superficial expansion (β) is related to the linear expansion by the equation \( \beta = 2\alpha \).
The coefficient of cubical expansion (γ) is related to the linear expansion by the equation \( \gamma = 3\alpha \).
Calculate both the superficial and cubical expansion coefficients using these relations.
Explanation:
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Answer:
1.025 this is the answer may be