. A milk vendor has 24 litres of cow milk, 42 litres of toned milk and 63 litres of double toned milk. If he wants to pack them in cans so that each can contains same litres of milk and does not want to mix any two kinds of milk in a can, then the least number of cans required is??
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Verified answer
Answer:
Step-by-step explanation:
Given,
Quantity of cow milk = 24 litres
Quantity of toned milk = 42 litres
Quantity of double toned milk = 63 litres
To Find,
The least number of cans required.
Solution,
For the maximum number, we take the HCF of given quantities.
HCF (24, 42, 63) = 3
Maximum capacity of a can = 3 litres
Now, least number of cans required by each milk,
Number of cans of cow milk,
= 24/3
= 8
Number of cans of toned milk,
= 42/3
= 14
Number of cans of double toned milk,
= 63/3
= 21
Then, Total number of cans,
= 3 + 8 + 14
= 25
Hence, the Total number of cans is 25.