A mother is 24 years older than her son.. After 4 years, the age of mother will be three times the age of his son.. Find the present age of both the mother and the son. .
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A mother is 24 years older than her son.. After 4 years, the age of mother will be three times the age of his son.. Find the present age of both the mother and the son. .
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Let the age of son = x
Then age of mother is = x+24
After four years:
Age of son = x+4
Age of mother = 3(x+4)
ie 3(x+4) = x+24+4
3x+12 = x+28
ie 2x = 16 and x=8.
Therefore son is 8 years old and mother is 32.