A moving body with a mass mi
strikes a stationary body of mass m2. The masses mi and
mi
m2 should be in the ratio
m2
so as to decrease the velocity of the first body 1.5 times
assuming a perfectly elastic impact. Then the ratio
mi
is
m2
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A moving body with a mass mi
strikes a stationary body of mass m2. The masses mi and
mi
m2 should be in the ratio
m2
so as to decrease the velocity of the first body 1.5 times
assuming a perfectly elastic impact. Then the ratio
mi
is
m2
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Answer:
Let initial velocity of mass m
1
be u
1
and its final velocity be v
1
the initial velocity for mass m
2
is zero and let it's final velocity be v
2
,
According to law of conservation of momentum ,
m
1
×u
1
+m
2
×u
2
=m
1
×v
1
+m
2
×v
2
or
m
1
×u
1
=m
1
×v
1
+m
2
×v
2
(since, u
2
=0)
According to the equation for coefficient of restitution for a perfectly elastic collision, we have
v
2
−v
1
=(u
1
)
solving both the equations gives the relation
(m
1
+m
2
)
(m
1
−m
2
)
=
u
1
v
1
=
3
2
Applying componendo and dividendo, we have
m
2
m
1
=
3−2
3+2
=
1
5
m
2
m
1
=5
Answer:
the question is wrong because the mass is 2 be 6 then it is a right question