a neutron moving with velocity v collides with a stationary alpha particle . the velocity of neutron after collision [assume the collision tobe perfectly elastic]...
a neutron moving with velocity v collides with a stationary alpha particle . the velocity of neutron after collision [assume the collision tobe perfectly elastic]...
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Q value of reaction is
Q=2Kα−KpQ=2Kα−Kp
Therefore , Q=(2×4×7.06−7×5.6)Q=(2×4×7.06−7×5.6)
=17.28MeV=17.28MeV
Where KpKp & KαKα are kinetic energies of photon and αα particle respectively . By conservation of linear momentum
Ko
2mpKp−−−−−−√=22mαKα−−−−−−√cosθ2mpKp=22mαKαcosθ
Kp=16Kαcos2θ=KαKp=16Kαcos2θ=Kα
according to the condition alpha paticle is at rest so its velocity is zero
now the final velocity of neutron is calculated from this formula
v' = (m1-m2÷ m1+m2) v1
by putting
v' = (1-4÷1+4) v
= -3/5 v
Negative sign shows reverse direction of neutro.