A number from 1 to 10 is chosen at random. Find the probability of choosing,
a) the prime number. b) the number greater than 10
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A number from 1 to 10 is chosen at random. Find the probability of choosing,
a) the prime number. b) the number greater than 10
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The numebers chosen are from 1 to 10.
Then possible outcomes are: 1,2,3,4,5,6,7,8,9,10
The probability of chosen a 5 OR and even number = probability of chosen a 5 + probability of chosen an even number.
Let us calculate each event:
P ( 5) = 1/10
Even number are: 2,4,6,8,10
==> P(even) = 5/10
Then :
P( 5 OR even) = P(5) + P(even)
= 1/10 + 5/10 = 6/10
= 3/5
==> P ( 5 or even) = 3/5
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Step-by-step explanation:
total numbers are 10,
so total possible outcome = 10
now,
1)
the event A can be noted as the choosing the number which is prime,
here favourable outcomes = 1,2,3,5,7
numbers = 5
so P(A) = favourable out come/ total outcome
P(A) = 5/10
P(A) = 1/2
2)
event B is number is greater than 10,
here there is no number is greater than 10
so,
favourable out come is 0
so,
P(A) = 0/10
P(A) = 0
(impossible event, so probability is zero)
hope this will help you.
Thank you
Happy to help.