A number is increased by 20% and then decreased by 20%. Find the net increase or
decrease in percentage.
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A number is increased by 20% and then decreased by 20%. Find the net increase or
decrease in percentage.
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Answer:
The answer is 4% .
Let the number be x.
1st step : It is increasedd by 20% .
Amount if increase = (20/100)*x
THerefore,the number now after increase = Previous value+amount increased
=x+(20/100)*x =(120/100) *x
2nd step: The resultant number is again decreased by 20% .
Amount decreased= (20/100)*(120/100)*x = 24x/100
The number now = (120/100) x- (24/100)x =96x/100
Now the original number was x and now it is 96x/100.
so net decrease = x-96x/100
Percentage decrease =(net decrease/ original value)* 100
=4%