a part of Rs 60000 was invested at 12% p.a. for 5 years and the rest was invested at 10% p.a. for 4 years l. if the total interest earned was Rs 27000, find the sum of money invested at each rate.
a part of Rs 60000 was invested at 12% p.a. for 5 years and the rest was invested at 10% p.a. for 4 years l. if the total interest earned was Rs 27000, find the sum of money invested at each rate.
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Answer:
X= 15000 , y=45000, x+y = 60000
Step-by-step explanation:
let x+y =60000
but given
x*( 12/100)*5+y*(10/100)*4=27000
3x/5+2x/5 =27000
3x+2y=135000
x+2(x+y)=135000
x+120000=135000
x=15000
y=45000
Answer:
15000 at 12% and 45000 at 10%
Step-by-step explanation:
Consider x be the first part of the investment,
Principal, P = x,
Rate of interest, r = 12%,
Time, t = 5 years,
So, the interest,
Now consider the second part of the investment is y,
P = y, r = 10%, t = 4 years,
Then interest,
According to the question,
............(1)
Also, total investment = 60,000
⇒ x + y = 60,000 ............(2),
Equation (1) - 3 × equation (2),
-y = 135000 - 180000
y = 45,000
From equation (2),
x + 45000 = 60,000
⇒ x = 15000
Hence, investment at 12% is rs 15,000 and at 10% is 45,000
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