A particle of mass 2 kg falls from height of 20 cm on a concrete floor and comes to rest after striking it. What is the momentum that is transferred to the floor?
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A particle of mass 2 kg falls from height of 20 cm on a concrete floor and comes to rest after striking it. What is the momentum that is transferred to the floor?
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Answer:
4 kgm/s
Explanation:
Given,
A particle of mass 2 kg falls from height of 20 cm on a concrete floor and comes to rest after striking it.
First let us find the momentum of the particle when it hits the concrete floor.
p = mv
p = m√2gh
p = 2√2(10)(20×10^-2)
p = 2√4
p = 4 kgm/s
By the conservation of angular momentum,
Initial momentum before collision = Final momentum after collision
pi(particle) + pi(surface) = pf(particle) + pf(surface)
4 + 0 = 0 + pf(surface)
pf(surface) = 4 kgm/s
Hence, momentum transferred to the surface = 4 kgm/s