A person starts a job with some fixed salary and yearly increment.
After 4 years his salary is Rs.15000 and after 10 years it becomes Rs.
18000. Then find his monthly salary and increment.
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A person starts a job with some fixed salary and yearly increment.
After 4 years his salary is Rs.15000 and after 10 years it becomes Rs.
18000. Then find his monthly salary and increment.
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Answer:
after 4 years his salary is Rs 15000
after 10 years his salary is Rs 18000
so, increments in (10-4) years=6 years is
Rs (18000-15000)=Rs 3 000
increment in 6 years is Rs 3000
increments in 1 years is Rs 3000/6=Rs 500
increments in 4 years Rs 3000×4/6=Rs 2000
so his current salary is (15000-2000)Rs= Rs 13000
his increments is Rs 500
Answer:
Let the starting salary of the man be Rs. x and the fixed annual increment be Rs. y. Then,
Salary after 4 years of service =Rs. (x+4y)
Salary after 10 years of service =Rs. (x+10y)
∴x+4y=15000 (i)
x+10y=18000 (ii)
Substracting equation (i) from equation (ii), we get
6y=3000⇒y=500
Putting y=500 in equation (i), we get x=13000.
Hence the starting salary was Rs. 13000 and annual increment is Rs. 500.
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