a person walk along the sides of a square field Each side is 100 m long . what is the maxi mein magnitude of displacement of the person in anytime interval
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a person walk along the sides of a square field Each side is 100 m long . what is the maxi mein magnitude of displacement of the person in anytime interval
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When a person walks along the sides of a square field, the maximum magnitude of displacement occurs when the person walks diagonally across the field. This diagonal is equivalent to the hypotenuse of a right triangle, where each side of the square forms one of the triangle's legs.
Given that each side of the square field is 100 meters long, we can use the Pythagorean theorem to find the magnitude of displacement (D) when walking diagonally:
D² = (Side 1)² + (Side 2)²
D² = 100² + 100²
D² = 10,000 + 10,000
D² = 20,000
Now, take the square root of 20,000 to find the magnitude of displacement:
D = √20,000
D ≈ 141.42 meters
So, the maximum magnitude of displacement of the person in any time interval is approximately 141.42 meters when they walk diagonally across the square field.
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Explanation:
Square field have 4 sides, each side is of 100m.
And as it is mentioned in question that he cover 1 round.
Distance- 100+100+100+100
= 400m.
Displacement- 0
Because after one round he reached to his starting position.