A planet of mass m is revolving around the sun
in a circle of radius r. What is the work done by
the gravitational force F in moving the planet
over half the circumference of the circle?
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A planet of mass m is revolving around the sun
in a circle of radius r. What is the work done by
the gravitational force F in moving the planet
over half the circumference of the circle?
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Explanation:
Work done is equal to zero assuming earth revolves around the sun in a perfect circle.
As Work=Force∗Displacement∗cosθ
Where θ is the angle between force and displacement .
In this case θ=90degree
As centripetal force is involved where earth is pulled towards the sun and direction of motion at each point is tangential to the orbit and as tangent makes 90degree with radius θ=90degree
Cos90
o
=0
Thereby F∗S∗cos90=F∗S∗0=0
HENCE NO WORK IS DONE .
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