A polynomial P(y) is given as ay^12+by^5-c , where a , b and c are natural numbers.
Is 0 a zero of p(y)
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A polynomial P(y) is given as ay^12+by^5-c , where a , b and c are natural numbers.
Is 0 a zero of p(y)
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Answer:
no, 0 is not a zero of this polynomial.
Step-by-step explanation:
for 0 to be a zero, p(0) needs to be equal to zero.
but p(0)=a(0)^12+b(0)^5-c
=-c
Since the result is not 0, therefore, 0 is not a zero of p(y)
Hope it helps
Answer
The number of zeroes of p(x) is the number of times the curve intersects the x-axis, i.e; attains the value 0.
Here, the polynomial p(x) meets the x-axis at 1 point.
So, number of zeroes =1...