A quantity is given by Q = sinx + cosx. Maximum value of Qis
1
√2
√3
1√2
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A quantity is given by Q = sinx + cosx. Maximum value of Qis
1
√2
√3
1√2
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Answer:
√2 is ans
Explanation:
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Given:
Q = sinx + cosx
To Find:
Maximum value of the given function ?
Solution:
Q = sinx + cosx
[ According to trigonometry;
Maximum value for sin and cos function is given by,
let a function f(x) = asinx + b cosx
Thus, maximum f(x) = [tex]\sqrt{a^{2} +b^{2} }[/tex] ]
Therefore, in given question,
a = 1 ; b = 1
maximum Q = [tex]\sqrt{1^{2} +1^{2} }[/tex]
= [tex]\sqrt{2}[/tex]
Hence the maximum value of Q will be [tex]\sqrt{2}[/tex] .