a radioactive element 90R232 emits one alpha and 2 beta particles. the daughter element will have
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a radioactive element 90R232 emits one alpha and 2 beta particles. the daughter element will have
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Explanation:
therefore
mass numberof daughter element = INITIAL MASS NUMBER (A) - 4 ( for 1 alpha)
= 232-4 = 228
atomic number of daughter element =
INTIAL ATOMIC NUMBER - 2(for 1 alpha) + 2 ( for 2 beta )
= 90-2+2 = 90