A ray of light enters into benzene from air. If the refractive index of benzene is 1.50, by what percent does the speed of light reduce on entering the benzene?
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A ray of light enters into benzene from air. If the refractive index of benzene is 1.50, by what percent does the speed of light reduce on entering the benzene?
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= (3-2)×10^8/3×10^8 ×100
=33.333333333333333333333333333333333333333333333333333333333333333333333333333333333333334%
Answer:
33.3 % .
Explanation:
Given :
Refractive index of benzene = 1.50
We know :
Speed of light = 3 × 10⁸ m / sec
We know formula for n :
n = speed of light in vacuum / speed of light in benzene
n = c / v
1.5 = 3 × 10⁸ / v
v = 2 × 10⁸ m / sec
Now ,
Percentage ( % ) decrease = 1 × 10⁸ / 3 × 10⁸ × 100 %
% decrease = 33.3 % .