A ray of light is incident on a plane surface of refractive index √3 at certain angle. It is found that the reflected and refracted rays are perpendicular to each other. Then the angle of incidence is?
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Class 10 : physics
Chapter : Refraction
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Explanation:
In this scenario, when a ray of light is incident on a plane surface with a refractive index of √3, and the reflected and refracted rays are perpendicular to each other, it means the angle of incidence is the critical angle (C).
In this scenario, when a ray of light is incident on a plane surface with a refractive index of √3, and the reflected and refracted rays are perpendicular to each other, it means the angle of incidence is the critical angle (C).The critical angle is the angle of incidence at which the angle of refraction is 90 degrees (perpendicular). The relationship between the critical angle (C) and the refractive index (n) is given by:
In this scenario, when a ray of light is incident on a plane surface with a refractive index of √3, and the reflected and refracted rays are perpendicular to each other, it means the angle of incidence is the critical angle (C).The critical angle is the angle of incidence at which the angle of refraction is 90 degrees (perpendicular). The relationship between the critical angle (C) and the refractive index (n) is given by:n = 1 / sin(C)
In this scenario, when a ray of light is incident on a plane surface with a refractive index of √3, and the reflected and refracted rays are perpendicular to each other, it means the angle of incidence is the critical angle (C).The critical angle is the angle of incidence at which the angle of refraction is 90 degrees (perpendicular). The relationship between the critical angle (C) and the refractive index (n) is given by:n = 1 / sin(C)In this case, n = √3. So,
In this scenario, when a ray of light is incident on a plane surface with a refractive index of √3, and the reflected and refracted rays are perpendicular to each other, it means the angle of incidence is the critical angle (C).The critical angle is the angle of incidence at which the angle of refraction is 90 degrees (perpendicular). The relationship between the critical angle (C) and the refractive index (n) is given by:n = 1 / sin(C)In this case, n = √3. So,√3 = 1 / sin(C)
In this scenario, when a ray of light is incident on a plane surface with a refractive index of √3, and the reflected and refracted rays are perpendicular to each other, it means the angle of incidence is the critical angle (C).The critical angle is the angle of incidence at which the angle of refraction is 90 degrees (perpendicular). The relationship between the critical angle (C) and the refractive index (n) is given by:n = 1 / sin(C)In this case, n = √3. So,√3 = 1 / sin(C)To find the angle of incidence (C), you can take the inverse sine (sin^(-1)) of (√3):
In this scenario, when a ray of light is incident on a plane surface with a refractive index of √3, and the reflected and refracted rays are perpendicular to each other, it means the angle of incidence is the critical angle (C).The critical angle is the angle of incidence at which the angle of refraction is 90 degrees (perpendicular). The relationship between the critical angle (C) and the refractive index (n) is given by:n = 1 / sin(C)In this case, n = √3. So,√3 = 1 / sin(C)To find the angle of incidence (C), you can take the inverse sine (sin^(-1)) of (√3):C = sin^(-1)(√3)
In this scenario, when a ray of light is incident on a plane surface with a refractive index of √3, and the reflected and refracted rays are perpendicular to each other, it means the angle of incidence is the critical angle (C).The critical angle is the angle of incidence at which the angle of refraction is 90 degrees (perpendicular). The relationship between the critical angle (C) and the refractive index (n) is given by:n = 1 / sin(C)In this case, n = √3. So,√3 = 1 / sin(C)To find the angle of incidence (C), you can take the inverse sine (sin^(-1)) of (√3):C = sin^(-1)(√3)C is approximately 60 degrees.
In this scenario, when a ray of light is incident on a plane surface with a refractive index of √3, and the reflected and refracted rays are perpendicular to each other, it means the angle of incidence is the critical angle (C).The critical angle is the angle of incidence at which the angle of refraction is 90 degrees (perpendicular). The relationship between the critical angle (C) and the refractive index (n) is given by:n = 1 / sin(C)In this case, n = √3. So,√3 = 1 / sin(C)To find the angle of incidence (C), you can take the inverse sine (sin^(-1)) of (√3):C = sin^(-1)(√3)C is approximately 60 degrees.So, the angle of incidence is approximately 60 degrees.
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Answer:
A ray of light is incident on a plane surface of refractive index √3 at certain angle. It is found that the reflected and refracted rays are perpendicular to each other. Then the angle of incidence is?
Note : Answer it if you know the correct answer. wrong answers will be reported. correct answer will be mark as Brainliest.
Class 10 : physics
Chapter : Refraction
Explanation:
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