A ray of light is incident on the plane mirror at rest. The mirror starts turning at a uniform
acceleration of 2π rads-2
. The reflected ray, at the end of ¼ s must have turned through:
plz answer quickly
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A ray of light is incident on the plane mirror at rest. The mirror starts turning at a uniform
acceleration of 2π rads-2
. The reflected ray, at the end of ¼ s must have turned through:
plz answer quickly
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Verified answer
α=2πrad/sec
2
Initially when mirror is at A position, lets incident ray makes an angle θ with normal.
Now, in case of B, mirror turned by,
θ=
2
1
×2π×(
2
1
)
2
=
16
π
rad
So, in this case i makes, (θ+
16
π
)
Angle with N
′
(new normal) also, refracted ray makes (
16
π
+θ) angle with N
′
.
Previously r makes θ angle with N and now N makes
16
π
rad angle with N
′
.
thereforer makes [(θ+
16
π
)+(
16
π
−θ)]㎭
angle with r.
that is,
16
π
+θ−θ+
16
π
=
8
π
=22.5°
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