A rectangular display board depicting ‘’BE DISCIPLINED’’ is kept
near the main gate of the school. The perimeter of a rectangular
board is 58m. Its length is 2 m more than twice its breadth.
(i) If the breadth of the rectangle is x m
ii) Perimeter in terms of x is
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Answer:
i) Breadth=9m, Length=20m ii) 2 (3x+2)
Step-by-step explanation:
Breadth = x m
Length = 2x+2 m (According to question)
i) We know,
Perimeter of a rectangle = 2 (l+b)
So, 2 (2x+2+x) = 58
= 2 (3x+2) = 58
= 3x+2 = 58/2
= 3x+2 = 29
= 3x = 27
x = 27/3 = 9 m
Breadth = x = 9 m
Length = 2x+2 = 2×9+2 = 20 m
ii) = 2 (2x+2+x)
= 2 (3x+2)
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