a rectangular is formed by 100cm wire. find out the maximum area of the rectangle.
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a rectangular is formed by 100cm wire. find out the maximum area of the rectangle.
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length of wire is 100 cm
length of wire = perimeter of rectangle
[tex]100 = 2(l + b) \\ l + b = \frac{100}{2} \\ l + b = 50[/tex]
we have to find maximum area . So, let
l = b .
Then,
[tex]l + b = 50 \\ l + l = 50 \\ 2l = 50 \\ l = \frac{50}{2} \\ l = 25 \\ l = b = 25 \: cm[/tex]
Area of ∆
[tex] = l \times b \\ = 25 \times 25 \\ = 625 \: { cm}^{2} [/tex]
Maximum area of ∆ is 625 cm² .
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Answer:
length of a wire=100cm
perimeter of rectangle=2(L+B)
NOW,
when we take L=B the values are same.
NOW, Area of a rectangle=L×B
So,area of a rectangle=625cm^2