A retarding force is applied to stop a motor car if the speed of the motor car is doubled how much more distance will it cover before stopping under the same retarding FORCE?
No spam
Give correct answers
Share
A retarding force is applied to stop a motor car if the speed of the motor car is doubled how much more distance will it cover before stopping under the same retarding FORCE?
No spam
Give correct answers
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
NO spam⚠️⚠️⚠️⚠️⚠️
Answer:
Work done against retarding force =Loss in K.E. In first case, F×s=12mυ2 ...(i) In second case, F×s′=12m(2υ)2 ..(ii) From (i) and (ii), s′= 4s Thus the motor car will cover a distance four times longer than before....
it's help u... plz mark me...
♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦
work done against retarding force = Loss of K.E.
in first case,
.....i
in second case,
......ii
From i and ii,
Thus the motor car will cover a distance four times longer than before.
♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦♦