a) Sanya,Aarushi,Manav and Kabir made greeting card. Complete the table for their cards:
Whose card Length width perimeter area
Sanya. 10cm. 8cm
Manav. 11cm. 44cm
Aarush. 8cm. 80 square cm
Kabir. 40cm 100 square cm
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a) Sanya,Aarushi,Manav and Kabir made greeting card. Complete the table for their cards:
Whose card Length width perimeter area
Sanya. 10cm. 8cm
Manav. 11cm. 44cm
Aarush. 8cm. 80 square cm
Kabir. 40cm 100 square cm
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Answer:
whose card Length width perimeter Areas
sanya 10 cm 8 cm 36 cm 80 sq.cm
Manav 11 cm 11 cm 44 cm 121 sq.cm
Aarushi 10 cm 8 cm 36 cm 80 sq.cm
Kabir 10 cm 10 cm 40 cm 100 sq.cm
sanya
we have length = 10 cm and width = 8 cm
perimeter =2(2+b)
= 2(10+8) = 2(18)
= 36 cm
Length of Manav's card =11 cm
Perimeter of his card =44 cm
Perimeter of card = sum of all its sides
=11+11+sum of other 2 sides
= 22+sum of other 2 sides
Now, sum of other two sides, 44-22=22 cm
so, width of manav's card =22/2, 11 cm
width of Arushi's card = 8 cm Area of card
=8×10=80cm
2
Now, we have to find length
Area of the card =80 cm
Length of Arushi's card = 80/8=10 cm.