A satellite of mass 200 kg revolving in a circular orbit of radius 2R around the earth has kinetic energy E. Then it's angular momentum will be
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A satellite of mass 200 kg revolving in a circular orbit of radius 2R around the earth has kinetic energy E. Then it's angular momentum will be
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Given that,
It is given that, a satellite of mass 200 kg revolving in a circular orbit of radius 2R around the earth has kinetic energy E.
To find,
Angular momentum of the satellite.
Solution,
The kinetic energy of the satellite is given by :
[tex]E=\dfrac{1}{2}mv^2[/tex] .....(1)
v is speed of satellite
Equation (1) can be rearranged as :
[tex]mv=\sqrt{2mE}[/tex] .......(2)
The angular momentum of the satellite is given by :
[tex]L=mvr[/tex]
Putting equation (2) in above formula as :
[tex]L=r\sqrt{2mE}[/tex]
Putting, r = 2R and m = 200 kg we get :
[tex]L=2R\sqrt{2\times 200E}\\\\L=40R\sqrt{E}[/tex]
So, the angular momentum of the satellite is [tex]40R\sqrt{E}[/tex].
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A satellite of mass 200 kg revolving in a circular orbit of radius 2R around the earth has kinetic energy E. Then it's angular momentum will be ?
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