A solution of 44 litres contain acid and water in the ratio5:6.If 4 litre of solutions is replaced with acid then what is the quantity of acid in new mixture?
A solution of 44 litres contain acid and water in the ratio5:6.If 4 litre of solutions is replaced with acid then what is the quantity of acid in new mixture?
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Answer:
Step-by-step explanation:
Acid:water=5:6
Given solution =44
Amount of acid=(5/11)*44----->20
Amount of water=(6/11)*44----->24
Now 4 liters are removed hence the solution becomes =40
Now we have to calculate the amount of acid in the 40 liters
Amount of acid=(5/11)*40----->18.18
As given in the question 4 extra liters of acid are added and hence the solution finally consists of -------> 18.18+4=22.18 liters.