A specific gravity bottle weighs 345.8g when empty. It is filled with 225ml of carbon tetrachloride. The weight of the specific gravity bottle with carbon tetrachloride is found to be 703.55g Calculate the density of carbon tetrachloride.
With explaination..
Share
Answer:
pls mark me brainliest
Explanation:
Step-by-step explanation:
\orange{\bold{\underbrace{\overbrace{❥Question᎓}}}}
❥Question᎓
Integrate the function
\huge\green\tt\frac{ \sqrt{tanx} }{sinxcosx}}
⇛\huge\tt\frac{ \sqrt{tanx} }{sinxcosx}
sinxcosx
tanx
ㅤ ㅤ ㅤ ㅤ ㅤ
⇛\huge\tt \frac{ \sqrt{tanx} }{sinxcosx \times \frac{cosx}{cosx}}
sinxcosx×
cosx
cosx
tanx
ㅤ ㅤ ㅤ ㅤ ㅤ
⇛\huge\tt \frac{ \sqrt{tanx} }{sinx \times \frac{ {cos}^{2} x}{cosx}}
sinx×
cosx
cos
2
x
tanx
ㅤ ㅤ ㅤ
⇛ \huge\tt\frac{ \sqrt{tanx} }{ {cos}^{2} x \times \frac{sinx}{cosx} }
cos
2
x×
cosx
sinx
tanx
ㅤ ㅤ ㅤ ㅤ ㅤ
⇛\huge\tt\frac{ \sqrt{tanx} }{ {cos}^{2}x \times tanx }
cos
2
x×tanx
tanx
⇛\huge\tt {tan}^{ \frac{1}{2} - 1 } \times \frac{1}{ {cos}^{2} x}tan
2
1
−1
×
cos
2
x
1
ㅤ ㅤ ㅤ ㅤ ㅤ
⇛\huge\tt {(tan)}^{ - \frac{ 1}{2} } \times \frac{1}{ {cos}^{2}x } = {(tanx)}^{ - \frac{1}{2} } \times {sec}^{2} x⇛(tan)(tan)
−
2
1
×
cos
2
x
1
=(tanx)
−
2
1
×sec
2
x⇛(tan)
ㅤ ㅤ ㅤ ㅤ ㅤ
⇛\huge\tt {(tan)}^{ - \frac{ 1}{2} } \times \frac{1}{ {cos}^{2}x } = ∫ {(tanx)}^{ - \frac{1}{2} } \times {sec}^{2} x \times dx⇛(tan)(tan)
−
2
1
×
cos
2
x
1
=∫(tanx)
−
2
1
×sec
2
x×dx⇛(tan)
ㅤ ㅤ ㅤ ㅤ ㅤ
\bold\blue{☛\: Let tanx=t}☛Lettanx=t
\bold\blue{☛ \:Differentiating \: both \: sides \: w.r.t.x}☛Differentiatingbothsidesw.r.t.x
ㅤ ㅤ ㅤ ㅤ ㅤ
⇛\huge\tt {sec}^{2} x = \frac{dt}{dx}sec
2
x=
dx
dt
⇛\huge\tt{dx \frac{dt}{ {sec}^{2}x }}dx
sec
2
x
dt
ㅤ ㅤ ㅤ ㅤ ㅤ
⇛\huge\tt∴∫ {(tanx)}^{ - \frac{1}{2} } \times {sec}^{2} x \times dx∴∫(tanx)
−
2
1
×sec
2
x×dx
⇛\huge\tt ∫ {(t)}^{ - \frac{1}{2} } \times {sec}^{2} x \times \frac{dt}{ {sec}^{2}x }∫(t)
−
2
1
×sec
2
x×
sec
2
x
dt
⇛\huge\tt ∫ {t}^{ - \frac{1}{2} }∫t
−
2
1
ㅤ ㅤ
⇛ \huge\tt\frac{ {t}^{ - \frac{1}{2} + 1} }{ - \frac{1}{2} + 1 }
−
2
1
+1
t
−
2
1
+1
⇛ \huge\tt \frac{ {t}^{ \frac{1}{2} } }{ \frac{1}{2} } + c = 2 {t}^{ \frac{1}{2} } + c = 2 \sqrt{t}
2
1
t
2
1
+c=2t
2
1
+c=2
t
⇛\huge2 \sqrt{t} + c = 2 \sqrt{tanx}2
t
+c=2
tanx
╚════════════════════════