A stone is released from the top of a building 78.4m high. Its final velocity just before touching the ground is
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A stone is released from the top of a building 78.4m high. Its final velocity just before touching the ground is
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Explanation:
GIVEN :-
Distance , s = 78.4m
Initial velocity , u = 0
final velocity , v = ?
According to Newton's third law of motion
===> v² = u² + 2gs
===> v² = ( 0 ) ² + 2 × 9.8 × 78.4
===> v² = 0 + 1536.64
===> v = √1536.64
===> v = 39.2 m/s
Here , g = acceleration due to gravity which is equal to 9.8 m/s .
Hence , final velocity , v is 39.2 m/s .