A student uses a lens of focal length 50 cm and another of – 20cm. Write the nature of and power of each lens.
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A student uses a lens of focal length 50 cm and another of – 20cm. Write the nature of and power of each lens.
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Explanation:
focal length= 50 cm
p= 1/f
p= 1/50
p= 0. 02 D
thus,nature of lens is convex .
focal length= -20 cm
p= 1/f
= 1/-20
= -0.05 D
thus, nature of lens is concave
hope it helps you
Given:-
To find:-
Concept to be applied:-
Formula for finding power:-
Here,
Solution:-
Power of lens 1 :-
power =
power = 2D
Power of lens 2 :-
power =
power = -5D
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Additional information:-