a sum of Rupees 390 was divided among 45 boys and girls. Each boy get Rs. 5, where as a girl get Rupees 10. Find the number boys and girls.
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a sum of Rupees 390 was divided among 45 boys and girls. Each boy get Rs. 5, where as a girl get Rupees 10. Find the number boys and girls.
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Given :- a sum of Rupees 390 was divided among 45 boys and girls. Each boy get Rs. 5, where as a girl get Rupees 10. Find the number boys and girls.
Answer :-
Let us assume that,
so,
→ x + y = 45 -------- Eqn.(1)
since, Each boy get Rs. 5, where as a girl get Rupees 10 and total amount is Rs.390 .
→ 5x + 10y = 390
→ 5(x + 2y) = 390
→ x + 2y = 78 ------- Eqn.(2)
subtracting Eqn.(1) from Eqn.(2)
→ (x + 2y) - (x + y) = 78 - 45
→ x - x + 2y - y = 33
→ y = 33 .
putting value of y in Eqn.(1)
→ x + 33 = 45
→ x = 45 - 33
→ x = 12 .
therefore, total number of b oys are 12 and total number of gi rls are 33.
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Given:
A sum of Rupees 390 was divided among 45 boys and girls. Each boy gets Rs. 5, whereas the girl gets rupees 10
To Find:
The number of Boys and Girls.
Solution:
Let the number of boys = B
Let the number of girls = G
It is given that there are total children = 45
=> B + G = 45 -------------(Equation 1)
It is given that a sum of Rs390 is divided. Each boy gets Rs.5, whereas the girl gets Rs.10.
=> 5B + 10G = 390
Take out 5 as common.
=> 5(B + 2G) = 390
=> B + 2G = 390/5
=> B + 2G = 78 ------------(Equation 2)
Finding the Number of Girls:
Subtract (Equation-1) from (Equation 2)
=> (B + 2G = 78) - (B + G = 45)
=> B + 2G - B - G = 78 - 45
=> G = 33
So, Girls = 33.
Finding the Number of Boys:
Substitute G=33 in (Equation 1)
=> B + G = 45
=> B + 33 = 45
=> B = 45 - 33
=> B = 12
So, Boys = 12
Hence, The number of Boys = 12, The number of Girls = 33