a) The sum of squares of first n natural numbers is given by n(n+1)(2n+1). Find the
6
sum of squares of the first 10 natural numbers.
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a) The sum of squares of first n natural numbers is given by n(n+1)(2n+1). Find the
6
sum of squares of the first 10 natural numbers.
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Answer:
a) The sum of squares of first n natural numbers
is given by n(n+1)(2n+1).
sum of squares of the first 10 natural numbers.
Step-by-step explanation:
so n(n+1)
n+n
2n+1
3n. 3n×10.
30n÷6. ans 5is natural number