A tower stand vertically on the ground. From a point on the ground 20 m away from the foot of the tower, the angle of elevation of the top of the tower is 60°. What is the height of the tower?
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A tower stand vertically on the ground. From a point on the ground 20 m away from the foot of the tower, the angle of elevation of the top of the tower is 60°. What is the height of the tower?
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Step-by-step explanation:
Here, AB is the height of a tower.
⇒ CB=20m
⇒ Now, tan60° = CB/AB
⇒√3 = AB /20
∴ AB=20 √3m
∴ Height of a tower is 20 √3 m.
Answer:
The height of the tower is 20√3 m.
Step-by-step explanation:
GIVEN:
Distance between point on the ground and foot of tower , BC = 20 m
Angle of elevation of the top of the tower, ∠ACB = 60°
Let AB = h m be the height of the tower
In right angle triangle, ∆ABC ,
tan C = AB/BC = P/ H
√3 = h/20
h = 20√3
AB = 20√3 m
Hence , the height of the tower is 20√3 m.