A tower stand verticle from the ground from a point on ground which is 100m away from the foot of tower and angle of elevation from the top of lower is found to be 60. Find the height of the tower.
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A tower stand verticle from the ground from a point on ground which is 100m away from the foot of tower and angle of elevation from the top of lower is found to be 60. Find the height of the tower.
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Step-by-step explanation:
To find the height of the tower, we can use trigonometry, specifically the tangent function. Given that the angle of elevation from the top of the tower is 60 degrees, and the distance from the point on the ground to the tower is 100 meters, you can set up the following equation:
tan(60 degrees) = height of the tower / distance from the tower to the point on the ground
tan(60 degrees) = h / 100
Now, solve for h (the height of the tower):
h = 100 * tan(60 degrees)
h ≈ 100 * √3 (since tan(60 degrees) = √3)
h ≈ 100 * 1.732 (approximately)
h ≈ 173.2 meters
So, the height of the tower is approximately 173.2 meters.
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