a trapezium shaped field whise parallel sides 42m 30m and other sides are 18m and 18m find its area
a trapezium shaped field whise parallel sides 42m 30m and other sides are 18m and 18m find its area
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Answer:
432 cm²
Step-by-step explanation:
Let the 4 sides of Trapezium to be A, B, C and D. Draw perpendiculars from A and B on the side CD of the trapezium at points E and F.
Length of EF would be equal to AB
DE and FC would be 6 cm each.
Apply Pythagoras Theorem in Δ ADE:-
(AD)² = (AE)² + (ED)²
(18)² = (AE)² + (6)²
324 = (AE)² + 36
(AE)² = 288
AE =
AE = 12 cm
So, the height of the triangle is 12 cm.
Find the area of both the triangles:-
= x b x h
= x 6 x 12
= 36 cm²
Area of the rectangle ABFE would be:-
= l x b
= 30 x 12
= 360 cm²
Area of Trapezium would be:-
= Area of 2 triangles + Area of rectangle
= 2(36 ) + 360
= 72 + 360
= 432 cm²
So, the area of the Trapezium is 432 cm² !
Note: Have a look at the attachment provided.