A vendar bought two wooden tables for 15,500 and paid 2 350 on transportation
He sold one table at a profit of 20%
and another at
at a lo
of 4% . Find
the selling price in both the cases
and the actual profit or loss percentage
made by the vendor
Share
A dealer bought two tables for Rs 3120. He sold one of them at a loss of 15% and other at a gain of 36%. Then, he found that each table was sold for the same price. What is the cost price of each table?
Friends…!
Let the cost price of one table be ₹x and other table be ₹y
He sold one of them at a loss of 15% and other at a gain of 36%
One table was sold at a loss of 15%. Hence it's sale price has been 85/100 × x = 0.85x
Other table was sold at a profit of 36%. Hence it's sale price 136/100 × y = 1.36y
he found that each table was sold for the same price
Thus 0.85 x = 1.36y
x = 1.36y/0.85…Eq..1
Dealer bought two tables for Rs 3120.
It means the cost price of two tabke together was ₹3120. Accordingly
x + y = 3120…Eq..2
Substituting the value if x from Eq.1 to Eq..2
x + y = 3120
1.36y/0.85 + y = 3120
(1.36y +
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Let 1st table cost Rs.x and 2nd table Rs.y
Since first table was sold at a loss of 15% it will
be 85x/100 and the 2nd one at a profit of 36% it will be 136y/100
As per the problem 85x/100 = 136y/100
Also x + y = 3120 (given)
Solving the two equation we get:
221y = 265200
Therefore y = 1200 and hence x= 1920
Hence the CP of the two tables is Rs 1200 and Rs. 1920.
(This method useful to you solve your questions)
thankyou