. A vessel is filled with two different liquids which do not mix. One liquid is 40 cm deep and has n1= 1.6
and the other is 30 cm deep and has n2 = 1.5. What is the apparent depth of the vessel when viewed along
the normal?
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. A vessel is filled with two different liquids which do not mix. One liquid is 40 cm deep and has n1= 1.6
and the other is 30 cm deep and has n2 = 1.5. What is the apparent depth of the vessel when viewed along
the normal?
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Answer:
70cm
Explanation:
When viewed along the normal there is no refraction taking place
Given : Two different liquids which do not mix
. Depth of first liquid = 40cm,n1 = 1.6
Depth of second liquid = 30cm, n2 = 1.6
To Find : Apparent depth of the vessel when viewed along
the normal.
Solution :
When viewed across the normal, there will be no refraction
Thus,
Apparent depth of the vessel when viewed along the normal is equal to actual depth
Actual Depth = Depth of first liquid + Depth of second liquid
Actual Depth = 40cm + 30 cm = 70cm
Apparent depth = actual depth = 70cm.
Hence apparent depth when viewed along the normal is 70cm.